You want the aggregate functions named min and max. If it is not possible, than is it possible to get max month and min month? (case when prevExt.FULL_INC is not null then (ext.FULL_INC - prevExt.FULL_INC) / prevExt.FULL_INC*100 else 0 end) as percentĪnd prevExt.cid = (select max (cid) from pl_extpayfileĪnd pl_extpayfile.employee = prevExt.employeeĪnd pl_extpayfile.employee = preext.employee When prevExt.FULL_INC is not null then (ext.FULL_INC -coalesce(prevExt.FULL_INC,0)) (extract(year from age (pl.fromdate))*12 +extract(month from age (pl.fromdate))) as month, From that I have to get min month, max month, and median month. 9.9.I have written a query in which one column is a month.or 12 p.m.? (FAQ - Time) (National Physical Laboratory )
When is it AM and when is it PM? (Arstechnica).How should “midnight on…” be interpreted? (English Language & Usage).If you are using dates together with the times, then find out which notation your RDBMS supports when adding a microsecond to either 11:59:59.999 or 11:59:59.999 p.m. This corresponds with your solution number 1. If you aren't using dates together with the time, then avoid using 00:00:00.000 as the notation for midnight following 23:59:59.999 (or the 11:59:59.999 p.m.)the same day. Input: select dateadd(ms,001,cast(' 23:59:59.999' as datetime))Īs you can see with the examples, both tested RDBMS systems determine 00:00:00.000 to be the time (after or roundabout) midnight but for the next day.
Input: postgres=# select TIMESTAMP ' 23:59:59.999' + interval '1 ms' Īdding a millisecond to a datetime value. as soon as the clock reaches midnight at 12 o'clock.Īdding a millisecond to a timestamp value. However, most systems decide to add an a.m. is midnight and is exactly 12 hours after midday or before the new midday. This is equally valid for the 12 hour notation around midnight. which is post-merdiem translates to after midday. is defined as ante-meridiem which translates to before midday, and p.m. Midday should actually have a single m added when static, seeing that a.m. Midday in 12 hour notation is neither am nor pm, even though clocks will tend to add a PM as soon as the clock jumps from 11:59:59.999 to 12:00:00.000. However, some RDBMS systems will switch the date when adding 0.001 s to 23:59:59.999. Following this logic the static value 00:00:00.000 should not belong to either day. Looking at the times around midnight you will find that 23:59:59.999 is still the same day, whereas 00:00:00.001 belongs to the next day. Midday is not an issue with the 24 hour notation because the step from 11:59:59.999to 12:00:00.000 and onward to 12:00:00.001 have no impact on the time format. Let me explain.ĭepending on whether you are using the 24 hour notation or the 12 hour am/pm notation the following bits of information might be equally interesting. 00:00:00.000 is considered to be the transition from one day to the next. You might want to consider that 23:59:59.999 belongs to the current day. Is there any other way to go about this? Some sort of special datetime function which accommodates this calculation? A better way to represent the data? Not a problem if it's the only solution, but feels like a drawback worth avoiding if possible. This seems pretty straightforward, but it makes it necessary to make one or more special indexes. I'll then do a query such as this: select from my_table where localtime >= start_time and localtime = start_time and (localtime < end_time or end_time = '00:00:00'). Id | bigint | not null default nextval('exploded_recurring_sessions_id_seq'::regclass) I have a table which represents time ranges.
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